Three friends are given three different numbers that add up to a dozen. Can you figure out everyone's numbers?

Three friends, Alice, Bob, and Charlie, are assigned three different positive whole numbers by their fourth friend, Diane. Furthermore, Diane told them that their three numbers add up to 12 and that Charlie's is the largest one.

Diane then asks the three of them if they know everyone's numbers, to which Bob replies βI do!β, whereas Alice and Charlie remain silent. After Bob's revelation, Alice and Charlie think for a couple of seconds and confirm that now they also know everyone's numbers.

What were Alice's, Bob's, and Charlie's numbers?

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For Bob to know Alice's and Charlie's numbers, Bob's number must be big enough so that Charlie's number doesn't have much wiggle room.

If Bob had the number 6, then Charlie would have at least 7 and their two numbers would add up to 13, which is already above 12. However, if Bob's number is 5, then Bob knows that Charlie can only have a 6 (if Charlie had 7 or more, then Bob and Charlie alone would add up to 12 or more) and hence Alice has to have a 1.

Thus, we conclude that Bob can guess everyone's numbers if Bob is given the 5.

From Alice's point of view, holding a 1 doesn't give her enough information to deduce what Bob and Charlie have, because they could have 2 and 9, for example, or 3 and 8.

From Charlie's point of view, holding a 6 doesn't give him enough information to deduce what Alice and Bob have, because they could have 1 and 5, or 2 and 4, for example, not to mention that Charlie wouldn't know who has the largest number.

After Bob announces he knows everyone's numbers, the other two can reverse engineer this reasoning and discover the missing numbers as well.

An alternative approach would be to list all possible number assignments and then look for the assignment that attributes a unique number to Bob. In other words, we can go through the numbers 1 to 12 and ask: βIf Bob had this number, in how many different ways could I attribute numbers to Alice and Charlie?β.

This problem was taken from this Reddit post, and shared with permission.

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