Today we are visiting a specific instance of a well-known basic mathematics game, the 24 Game. The "24 Game" is usually played with younger students because it helps them develop skills related to the basic arithmetic operations.
Problem statement
The "24 Game" is usually played with four different numbers from \(1\) to \(9\), for example drawn randomly out of a small deck with those numbers. For this blog post, you can forget about all that, I picked very specific numbers for you.
Using the four numbers \(3\), \(3\), \(8\) and \(8\) and the four arithmetic operations addition, subtraction, multiplication and division, you have to make an expression that evaluates to \(24\). The rules are simple:
- each number must be used exactly once;
- operations can be used any number of times (even zero times);
- the precedence of operations can be changed by the use of \(()\);
- numbers cannot be used by positioning them in a special way, e.g. you can't make \(33\) by joining the two \(3\)s and you can't make \(27\) by writing \(3^3\).
I am not giving you a puzzle with a cheap trick involved. This is pure arithmetics.
An example valid expression would be \((3+3)\times (8+8)\) except this is not the solution because it gives \(96\) instead of \(24\).
Give it some thought, maybe take out a piece of paper and a pencil.
Hint
Do not read the hint if you haven't spent some time thinking about the problem yet!
The intermediate steps do not have to evaluate to integer numbers.
Solution
There really is no point in sugar coating this for you, the solution is the expression \(8 \div (3 - 8\div 3)\). Quite ingenious, isn't it?
I heard of this from the same friend who told me about the "Fold the alphabet" problem.
Were you able to solve this problem? Let me know your thoughts in the comment section down below!
See you next time!
