This article shows you how to overload the arithmetic operators in Python with dunder methods.
Python lets you override the arithmetic operators like +
for addition or *
for multiplication through dunder methods.
Dunder methods are special methods whose name starts and ends with a double underscore (hence, “dunder”), and some dunder methods are specific to arithmetic operations.
In this Pydon't, you will learn:
p
);+p
);abs(p)
); and~
).+
);
);*
);/
);//
);%
);divmod
); andpow
).<<
);>>
);&
);
);^
);NotImplemented
is and how it differs from NotImplementedError
; andWe will start by explaining how dunder methods work and we will give a couple of examples by implementing the unary operators.
Then, we introduce the mechanics behind the binary arithmetic operators, basing the examples on the binary operator +
.
After we introduce all the concepts and mechanics that Python uses to handle binary arithmetic operators, we will provide an example of a class that implements all the arithmetic dunder methods that have been mentioned above.
You can now get your free copy of the ebook “Pydon'ts – Write elegant Python code” [on Gumroad][gumroadpydonts] to help support the series of “Pydon't” articles 💪.
The example we will be using throughout this article will be that of a Vector
.
A Vector
will be a class for geometrical vectors, like vectors in 2D, or 3D, and it will provide operations to deal with vectors.
For example, by the end of this article, you will have an implementation of Vector
that lets you do things like these:
>>> from vector import Vector
>>> v = Vector(3, 2)
>>> v + Vector(4, 10)
Vector(7, 12)
>>> 3 * v
(9, 6)
>>> v
(3, 2)
Let us go ahead and start!
This is the starting vector for our class Vector
:
# vector.py
class Vector:
def __init__(self, *coordinates):
self.coordinates = coordinates
def __repr__(self):
return f"Vector{self.coordinates}"
if __name__ == "__main__":
print(Vector(3, 2))
Running this code will show this output:
Vector(3, 2)
This starting vector also shows two dunder methods that we are using right off the bat:
__init__
to initialise our Vector
instance; and__repr__
to provide a string representation of our Vector
objects.This shows that dunder methods are not magical. They look funny because of the leading and trailing underscores in their names, but they are regular Python methods that Python calls automatically.
We will start by covering the unary arithmetic operations because those are simpler. Then, we will move along to the binary arithmetic operations. Good luck! 🐍🚀
Take a look at this piece of code:
>>> x = 73
>>> x
73
Does the result surprise you? Probably not!
Now, look at this:
>>> x = 73
>>> x.__neg__()
73
Was this surprising?
The method __neg__
is the dunder method that is responsible for implementing the unary operation of negation.
Currently, our class Vector
does not have support for the operation of negation:
>>> v = Vector(1, 2)
>>> v
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: bad operand type for unary : 'Vector'
If we implement a method __neg__
in our class Vector
, we can add support for this operation.
The method __neg__
only accepts the argument self
and should return the result of negating self
.
For illustrative purposes, we can start by implementing a method __neg__
that always returns "Hello, world!"
:
class Vector:
...
def __neg__(self):
return "Hello, world!"
Now, we can use the unary operation minus:
>>> Vector(1, 2)
'Hello, world!'
Of course, it doesn't make much sense for the negation of a vector to be the string "Hello, world!"
.
The unary negation we will implement for real will negate each coordinate, one by one:
class Vector:
...
def __neg__(self):
return Vector(*[coord for coord in self.coordinates])
This is a more sensible operation, which enables this:
>>> Vector(1, 2, 3, 4)
Vector(1, 2, 3, 4)
That's it! This was your first arithmetic dunder method! 🎉
Now, we'll implement the remaining unary arithmetic operations.
There are four unary arithmetic operations for a vector v
:
v
is negation and is implemented via __neg__
;+v
is implemented via __pos__
(I have no idea what it's called!);abs(v)
is the absolute coord and is implemented via __abs__
; and~v
is inversion and is implemented via __invert__
.These four dunder methods are all unary, which means the only argument they take is self
, which is going to be the instance of Vector
that they need to operate on.
__neg__
for negationThis one was already implemented above!
__pos__
When used on integers and floats, __pos__
acts as a noop:
>>> x = 73
>>> +x
73
>>> x.__pos__()
73
>>> x = 73
>>> +x
73
>>> x.__pos__()
73
So, we will do the same thing for vectors. However, because the other unary arithmetic operations return different instances, we will be sure to return a different instance that has the same coordinates:
class Vector:
...
def __pos__(self):
return Vector(*self.coordinates)
if __name__ == "__main__":
v = Vector(1, 2, 3)
print(+v) # Vector(1, 2, 3)
print((+v) is v) # False
__abs__
for the absolute valueThe dunder method __abs__
is called when we use the builtin abs
.
>>> 1 + 2j
(1+2j)
>>> abs(1 + 2j)
2.23606797749979
>>> (1 + 2j).__abs__()
2.23606797749979
For our class Vector
, we will return the magnitude of the vector, which is the square root of the sum of the squares of all the coordinates.
class Vector:
...
def __abs__(self):
return pow(sum(coord ** 2 for coord in self.coordinates), 0.5)
if __name__ == "__main__":
v = Vector(1, 2)
print(abs(v))
__invert__
for inversionThe dunder method __invert__
is called when the unary arithmetic operation ~
is used.
For integers, this operation is based on binary.
(Try to figure out what it does!)
For our class Vector
, we can do whatever we want.
The operation I'm implementing is inspired by geometry.
It looks like this:
class Vector:
...
def __invert__(self):
"""Compute a vector that is orthogonal to this one."""
if len(self.coordinates) <= 1:
raise TypeError(
f"Cannot invert vector of length {len(self.coordinates)}."
)
# Look for two nonzero coordinates to swap.
to_flip = [0, 1]
for idx, coord in enumerate(self.coordinates):
if coord:
to_flip.append(idx)
# Zero out all coordinates...
coordinates = [0] * len(self.coordinates)
# except the two we are swapping out.
coordinates[to_flip[1]] = self.coordinates[to_flip[2]]
coordinates[to_flip[2]] = self.coordinates[to_flip[1]]
return Vector(*coordinates)
What does this do? Given a vector, it will look for two coordinates that are not zero and it will swap them out, while also flipping the sign in one of them. All other coordinates of the result will be 0.
Here are some small examples:
>>> ~Vector(1, 2, 3)
Vector(0, 3, 2)
>>> ~Vector(1, 0, 3)
Vector(3, 0, 1)
>>> ~Vector(1, 0, 0)
Vector(0, 1, 0)
Here are some examples with longer vectors:
>>> ~Vector(1, 2, 3, 4, 5, 6, 7)
Vector(0, 0, 0, 0, 0, 7, 6)
>>> ~Vector(1, 0, 0, 0, 5, 0, 0)
Vector(5, 0, 0, 0, 1, 0, 0)
>>> ~Vector(0, 2, 0, 4, 0, 0, 7)
Vector(0, 0, 0, 7, 0, 0, 4)
This is not a random operation I came up with, it is something from geometry.
You can read this Wikipedia article to learn about "orthogonal vectors".
This will also make more sense when we implement the dunder method __matmul__
, later.
If you got to this point, it means you have implemented all unary arithmetic operations. Good job! 🚀
Here is all the code up until this point:
class Vector:
def __init__(self, *coordinates):
self.coordinates = coordinates
def __repr__(self):
return f"Vector{self.coordinates}"
def __matmul__(self, other):
return sum(c1 * c2 for c1, c2 in zip(self.coordinates, other.coordinates))
def __neg__(self):
return Vector(*[coord for coord in self.coordinates])
def __pos__(self):
return Vector(*self.coordinates)
def __abs__(self):
return pow(sum(coord**2 for coord in self.coordinates), 0.5)
def __invert__(self):
"""Compute a vector that is orthogonal to this one."""
if len(self.coordinates) <= 1:
raise TypeError(
f"Cannot invert vector of length {len(self.coordinates)}."
)
# Look for two nonzero coordinates to swap.
to_flip = [0, 1]
for idx, coord in enumerate(self.coordinates):
if coord:
to_flip.append(idx)
# Zero out all coordinates...
coordinates = [0] * len(self.coordinates)
# except the two we are swapping out.
coordinates[to_flip[1]] = self.coordinates[to_flip[2]]
coordinates[to_flip[2]] = self.coordinates[to_flip[1]]
return Vector(*coordinates)
Up until now, we dealt with unary operators.
This means that the operator expected a single object to work with.
As we delve into binary operators, the dunder methods we will implement will take two arguments: self
and other
.
This will be explained right away, as we start implementing addition.
__add__
To implement addition between our Vector
instances we need to implement the dunder method __add__
.
When Python finds an expression like a + b
, Python will try to run a.__add__(b)
, which is why we can use the dunder method __add__
to implement addition for our objects.
Because addition is a binary operator (you add two things), the dunder method __add__
takes two arguments:
self
; andother
.Remember:
a + b
turns into a.__add__(b)
, which is a regular method call!
So, b
will be the “other
” thing that we want to add to self
and will be passed in as an argument.
For our Vector
class, the signature of __add__
looks like this:
class Vector:
...
def __add__(self, other):
...
Now, instead of ...
we just need to provide the actual implementation.
Adding Vector
instances amounts to adding up all their respective coordinates:
class Vector:
...
def __add__(self, other):
result_coordinates = [a + b for a, b in zip(self.coordinates, other.coordinates)]
return Vector(*result_coordinates)
if __name__ == "__main__":
print(Vector(3, 2) + Vector(10, 4)) # Vector(13, 6)
I'm using a list comprehension and the builtin
zip
to go over the respective coordinates of each Vector
instance.
This is all it takes to implement a dunder method.
Now, the implementation we provided above is pretty barebones. For example, it is going to raise an interesting error if we try to add a vector to an integer:
>>> Vector(1, 2) + 3
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/Users/rodrigogs/Documents/vector.py", line 9, in __add__
result_coordinates = [a + b for a, b in zip(self.coordinates, other.coordinates)]
^^^^^^^^^^^^
AttributeError: 'int' object has no attribute 'coordinates'
We get an error because we assumed that other
was going to be an instance of a Vector
, but we tried to add a vector and an integer, and so our assumption didn't hold.
In general, you will want to use isinstance
to make sure you can do the operation you really want to do:
class Vector:
...
def __add__(self, other):
if isinstance(other, Vector):
result_coordinates = [a + b for a, b in zip(self.coordinates, other.coordinates)]
return Vector(*result_coordinates)
When we add this check, the error goes away entirely:
>>> from vector import Vector
>>> Vector(1, 2) + 3
>>> # It didn't error?!
That is also not quite what we wanted.
What we would like to see is one of those TypeError
s that the language raises when we mix types in the wrong way:
>>> 3 + "3"
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: unsupported operand type(s) for +: 'int' and 'str'
How do we raise this error?
You might think of actually raising the error yourself, with raise TypeError(...)
, but there is a builtin mechanism that does this.
NotImplemented
to flag operations you don't supportNotImplemented
When there is a combination of arguments that you do not have support for, you need to return the builtin constant NotImplemented
.
The NotImplemented
constant is like None
in the sense that it is builtin and that there is only one.
You don't instantiate None
values, you just use the value None
.
Similarly, you don't instantiate NotImplemented
values, you just use NotImplemented
.
If you need to return NotImplemented
if you do not know how to add the vector with the other argument, you need to modify the method __add__
like so:
class Vector:
...
def __add__(self, other):
if isinstance(other, Vector):
result_coordinates = [a + b for a, b in zip(self.coordinates, other.coordinates)]
return Vector(*result_coordinates)
return NotImplemented
You should return the value NotImplemented
.
Please, do not mistake this for returning the value NotImplementedError
or for raising the exception NotImplementedError
.
When you return NotImplemented
, you are telling Python that a vector cannot be added with whatever type other
was, so Python will take care of raising the appropriate TypeError
for you:
>>> from vector import Vector
>>> Vector(1, 2) + 3
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: unsupported operand type(s) for +: 'Vector' and 'int'
You can even see this is what happens behind the curtains with some builtin types!
For example, 3 + "hello"
raises an error, but (3).__add__("hello")
returns NotImplemented
:
>>> (3).__add__("hello")
NotImplemented
NotImplemented
and NotImplementedError
The two builtins NotImplemented
and NotImplementedError
may look similar, but they have very distinct use cases.
The builtin constant NotImplemented
is used only in the context of arithmetic dunder methods to tell Python that a specific operation can't be handled by a specific class, whereas the builtin exception NotImplementedError
is raised when you have defined the body of a function or a method to specify its signature, but you haven't implemented the behaviour yet.
This is useful, for example, when you use a class as an abstract base class and you specify the signatures of the methods that the subclasses will need, but you don't implement them because it is up to the subclasses to provide that behaviour.
Here is a short Shape
example:
class Shape:
def __init__(self, name):
self.name = name
def area(self):
raise NotImplementedError("Subclass must implement this method")
def perimeter(self):
raise NotImplementedError("Subclass must implement this method")
The Shape
specifies that all subclasses of the class Shape
must implement the methods area
and perimeter
:
class Rectangle(Shape):
def __init__(self, length, width):
super().__init__("Rectangle")
self.length = length
self.width = width
def area(self):
return self.length * self.width
def perimeter(self):
return 2 * (self.length + self.width)
rect = Rectangle(5, 3)
print(rect.area()) # 15
print(rect.perimeter()) # 16
Python has more complete mechanisms to handle abstract base classes (called interfaces, in other languages), but this small example illustrates the point.
Before taking this little tangent about the difference between NotImplemented
and NotImplementedError
, we saw that our vectors cannot be added to integers.
However, we wish to extend our implementation of Vector
to handle integer and float addition.
To add an integer or a float to a Vector
means that all coordinates of the Vector
get shifted by the given amount.
To implement that behaviour, we need to add an extra branch to our if
statement inside __add__
:
class Vector:
...
def __add__(self, other):
if isinstance(other, Vector):
result_coordinates = [a + b for a, b in zip(self.coordinates, other.coordinates)]
return Vector(*result_coordinates)
elif isinstance(other, (int, float)):
result_coordinates = [coord + other for coord in self.coordinates]
return Vector(*result_coordinates)
return NotImplemented
Now, Vector
instances can be added to numbers!
It works with integers:
class Vector:
...
if __name__ == "__main__":
print(Vector(1, 2) + 3) # Vector(4, 5)
It works with floats:
class Vector:
...
if __name__ == "__main__":
print(Vector(1, 2) + 3) # Vector(4, 5)
print(Vector(1, 2) + 4.5) # Vector(5.5, 6.5)
And it even works backwards:
class Vector:
...
if __name__ == "__main__":
print(Vector(1, 2) + 3) # Vector(4, 5)
print(Vector(1, 2) + 4.5) # Vector(5.5, 6.5)
print(3 + Vector(1, 2)) # Raises: TypeError: unsupported operand type(s) for +: 'int' and 'Vector'
Huh?
What do you mean?
We just implemented addition between instances of Vector
and int
...
Let us add a couple of print statements for debugging:
class Vector:
...
def __add__(self, other):
print(f"About to add {self} with {other}")
if isinstance(other, Vector):
result_coordinates = [a + b for a, b in zip(self.coordinates, other.coordinates)]
return Vector(*result_coordinates)
elif isinstance(other, (int, float)):
print(f"{other} is an int or a float!")
result_coordinates = [coord + other for coord in self.coordinates]
return Vector(*result_coordinates)
return NotImplemented
if __name__ == "__main__":
print("Vector plus int")
print(Vector(1, 2) + 3) # Vector(4, 5)
print()
print("Vector plus float")
print(Vector(1, 2) + 4.5) # Vector(5.5, 6.5)
print()
print("int plus Vector")
print(3 + Vector(1, 2)) # Raises: TypeError: unsupported operand type(s) for +: 'int' and 'Vector'
Now, if we rerun the file, we see... Nothing! This is the output:
Vector plus int
About to add Vector(1, 2) with 3
3 is an int or a float!
Vector(4, 5)
Vector plus float
About to add Vector(1, 2) with 4.5
4.5 is an int or a float!
Vector(5.5, 6.5)
int plus Vector
Traceback (most recent call last):
File "/Users/rodrigogs/Documents/vector.py", line 29, in <module>
3 + Vector(1, 2)
~~^~~~~~~~~~~~~
TypeError: unsupported operand type(s) for +: 'int' and 'Vector'
Notice that we get the error without seeing the prints from within __add__
...
And you know why?
Well, obviously because __add__
never got called.
Let me explain:
To be precise, when your arithmetic dunder method returns NotImplemented
, it tells Python that that specific method call failed.
For example, when Vector.__add__
returns NotImplemented
, it tells Python that the class Vector
does not know how to add vectors with whatever was in the argument other
.
However, when Python sees the return value NotImplemented
coming out of an arithmetic dunder method, Python does not raise the TypeError
exception immediately!
In fact, it will try to run a plan B, first.
When you write a + b
, Python will start by trying to run a.__add__(b)
.
If that fails (that is, if it returns NotImplemented
), Python will then try to run b.__radd__(a)
!
Notice that I wrote __radd__
with an extra r
, and not just __add__
.
__radd__
is the “reflected dunder dunder __add__
”, and it is like the plan B for addition.
So, when we wrote 3 + Vector(1, 2)
, Python started by trying to run (3).__add__(Vector(1, 2))
, which returns NotImplemented
:
>>> from vector import Vector
>>> (3).__add__(Vector(1, 2))
NotImplemented
Then, Python will try to run Vector(1, 2).__radd__(3)
.
Because we have not implemented that method, Python raises the exception TypeError
.
All other arithmetic dunder methods also have a “reflected” version which has the same name but with the letter r
prefixed.
Some examples of reflected dunder methods include:
__rsub__
which is the reflected dunder method for subtraction;__rmul__
which is the reflected dunder method for multiplication; or__rpow__
which is the reflected dunder method for exponentiation.So, all things considered, if we want to be able to write expressions like 3 + Vector(1, 2)
, we need to implement the dunder method Vector.__radd__
.
For our example, Vector(1, 2) + 3
is supposed to return the same value as 3 + Vector(1, 2)
, so we can implement __radd__
in terms of __add__
:
class Vector:
...
def __radd__(self, other):
print(f"Inside __radd__ with {self} and {other}")
return self + other
if __name__ == "__main__":
print(3 + Vector(1, 2))
If you run this code, it outputs the following:
Inside __radd__ with Vector(1, 2) and 3
About to add Vector(1, 2) with 3
3 is an int or a float!
Vector(4, 5)
In fact, because addition with instances of Vector
is commutative (that is, the result does not depend on the order of the left and right operands), you could even say that __radd__ = __add__
:
class Vector:
...
def __add__(self, other):
# Implementation omitted for brevity...
__radd__ = __add__
This would still work. Give it a try.
Not all arithmetic operations are commutative.
In fact, even addition isn't always commutative!
Addition of strings – which we call concatenation – isn't commutative because a + b
is usually different from b + a
:
>>> a = "Hello, "
>>> b = "world!"
>>> a + b
'Hello, world!'
>>> b + a
'world!Hello, '
When the operation isn't commutative, you have to implement the reflected dunder method like any other dunder method. You will see examples of this throughout this article.
NotImplemented
in reflected dunder methodsReverse dunder methods should also return NotImplemented
when the operation isn't defined for certain types of other arguments.
For example, if we were to implement __radd__
explicitly for Vector
, we would still return NotImplemented
at the end of the method.
Suppose that we didn't:
class Vector:
...
def __radd__(self, other):
print(f"About to radd {self} with {other}")
if isinstance(other, Vector):
result_coordinates = [a + b for a, b in zip(self.coordinates, other.coordinates)]
return Vector(*result_coordinates)
elif isinstance(other, (int, float)):
print(f"{other} is an int or a float!")
result_coordinates = [coord + other for coord in self.coordinates]
return Vector(*result_coordinates)
# return NotImplemented # < Do we need this?
Can you guess what's going to happen now? What should be the result of running the code below?
class Vector:
...
if __name__ == "__main__":
print("Adding a list and a vector:")
print([1, 2] + Vector(1, 2))
Addition between lists and vectors is not defined, so this should result in a TypeError
.
However, because Vector.__radd__
does not return NotImplemented
, Python actually thinks that this results in None
.
The output of running that code is:
Adding a list and a vector:
About to radd Vector(1, 2) with [1, 2]
None
What is happening here is that the method __radd__
has no explicit return at the end, which means the method returns None
when using __radd__
to add a Vector
to something else that isn't a Vector
, an integer, or a float.
If we want to get the TypeError
, we need to return NotImplemented
:
class Vector:
...
def __radd__(self, other):
print(f"About to radd {self} with {other}")
if isinstance(other, Vector):
result_coordinates = [a + b for a, b in zip(self.coordinates, other.coordinates)]
return Vector(*result_coordinates)
elif isinstance(other, (int, float)):
print(f"{other} is an int or a float!")
result_coordinates = [coord + other for coord in self.coordinates]
return Vector(*result_coordinates)
return NotImplemented # < We need this!
Now, when we run this code, Python gives us a great error message:
About to radd Vector(1, 2) with [1, 2]
Traceback (most recent call last):
File "/Users/rodrigogs/Documents/vector.py", line 43, in <module>
print([1, 2] + Vector(1, 2))
~~~~~~~^~~~~~~~~~~~~
TypeError: can only concatenate list (not "Vector") to list
There is another situation in which reflected dunder methods come in handy, and that is when the right operand is from a subclass of the left operand. Let me explain.
You are writing some code and you implement a class S
that just holds a string.
Then, you implement addition between instances of the type S
:
class S:
def __init__(self, value):
self.value = value
def __add__(self, other):
if isinstance(other, S):
return self.value + other.value
return NotImplemented
This works just fine:
>>> s1 = S("Hello, ")
>>> s2 = S("world!")
>>> s1 + s2
'Hello, world!'
Then, you decide to create a subclass of S
, called E
, which always holds the empty string.
Something like this:
class E(S):
def __init__(self):
super().__init__("")
Because E
is a subclass of S
, you can add instances of S
and E
without a problem:
>>> S("Hey") + E()
'Hey'
>>> E() + S("Hey")
'Hey'
>>> E() + E()
''
Everything is fine, right?
However, E
is always the empty string, which means that when you add an instance of E
to another instance of S
, the result is always the string saved in the other instance, right?
So, you could optimise addition with instances of the type E
by saying that you only need to return the string from the other instance.
Something like this:
class S:
def __init__(self, value):
self.value = value
def __add__(self, other):
print("S.__add__") # < Added this here.
if isinstance(other, S):
return self.value + other.value
return NotImplemented
class E(S):
def __init__(self):
super().__init__("")
def __add__(self, other):
print("E.__add__") # < Helper print.
if isinstance(other, S):
return other.value
return NotImplemented
def __radd__(self, other):
print("E.__radd__") # < Helper print.
if isinstance(other, S):
return other.value
return NotImplemented
Because this behaviour is more specialised and because it comes from a subclass of S
, Python will give priority to E
's way of adding things together if we try to add an instance of S
with an instance of E
:
>>> S("Oi") + E()
E.__radd__
'Oi'
Notice that we didn't see the print from S.__add__
because E.__radd__
has priority over S.__add__
.
That priority comes from the fact that E
is a subclass of S
.
To conclude, in an expression a + b
, the call b.__radd__(a)
will happen if:
a.__add__(b)
returned NotImplemented
; orb
is a subclass of the type of a
, in which case b.__radd__(a)
is called before a.__add__(b)
.In Python, we can write things like counter += 1
and multiplier *= 2
.
This is called augmented assignment and there are dunder methods used to implement this behaviour.
The dunder methods that are used for augmented assignment start with an “i”, which I am guessing stands for “inplace”.
The rationale for these methods is that they should try to do the operation inplace.
If it makes sense for your object to be modified in place, then you should implement the augmented arithmetic assignment dunder methods.
For example, for addition that is going to be __iadd__
.
Of course, augmented assignment works even without implementing the dunder method __iadd__
.
Try running this code:
if __name__ == "__main__":
v = Vector(1, 2)
print(v, id(v))
v += Vector(3, 4)
print(v, id(v))
The output should be the following:
❯ python point.py
Vector(1, 2) 4305034320
About to add Vector(1, 2) with Vector(3, 4)
Vector(4, 6) 4305036176
Notice two things:
print
from the dunder method __add__
; andThat is because, when running v += ...
, Python wants to do v.__iadd__(...)
but it can't, because we haven't implemented that method.
So, Python unrolls the augmented assignment and tries to evaluate v = v + ...
instead, which is why we saw that __add__
was called.
To provide a true augmented assignment implementation, we could write something like this:
class Vector:
...
def __iadd__(self, other):
if isinstance(other, Vector):
self.coordinates = tuple(
self_coord + other_coord
for self_coord, other_coord in zip(self.coordinates, other.coordinates)
)
return self
elif isinstance(other, (int, float)):
self.coordinates = tuple(coord + other for coord in self.coordinates)
return self
return NotImplemented
if __name__ == "__main__":
v = Vector(1, 2)
print(v, id(v))
v += Vector(3, 4)
print(v, id(v))
If you run this, the output you get is
❯ python point.py
Vector(1, 2) 4342701264
Vector(4, 6) 4342701264
As you can see, the ID of v
doesn't change because we implemented a true inplace dunder method.
Another thing to note is that even though we are modifying self
, we still need to return the result.
(Which is self
.)
In this section, we will take all of the knowledge from the previous sections and provide an example class that provides a full implementation of all the arithmetic operators and respective dunder methods:

*
/
//
%
divmod
**
/pow
@
<<
>>
&
^


The binary operator 
is the binary operator for subtraction.
It is common for addition and subtraction to be closely related and, when they are, you can exploit those relationships.
__sub__
, __rsub__
, and __isub__
for subtractionFor plain subtraction, we can realise that a  b
is just a + (b)
, and we already implemented the unary negation operator (with the dunder method __neg__
), so we can use that shortcut:
class Vector:
...
def __sub__(self, other):
return self + (other)
if __name__ == "__main__":
v = Vector(1, 2)
print(v  1)
print(v  Vector(1, 2))
This code produces the following output:
❯ python point.py
About to add Vector(1, 2) with 1
1 is an int or a float!
Vector(0, 1)
About to add Vector(1, 2) with Vector(1, 2)
Vector(0, 0)
Of course, because we implemented subtraction in terms of addition and negation, we get a bunch of prints from those dunder methods.
To implement reflected subtraction in terms of addition and negation, we need to be careful!
In Vector.__rsub__
, we will have self
and other
and we will be trying to compute other  self
, so we need to return other + (self)
:
class Vector:
...
def __rsub__(self, other):
return other + (self)
if __name__ == "__main__":
p = Vector(1, 2)
print(1  p)
This code produces the following output:
❯ python point.py
About to radd Vector(1, 2) with 1
1 is an int or a float!
Vector(0, 1)
Finally, to implement augmented subtraction, we can do it in terms of augmented addition:
class Vector:
...
def __isub__(self, other):
self += other
return self
if __name__ == "__main__":
v = Vector(1, 2)
print(v, id(v))
v = 2
print(v, id(v))
This produces the following output:
❯ python point.py
Vector(1, 2) 4372225424
Vector(1, 0) 4372225424
*
The binary operator *
is the operator for multiplication.
Multiplying a vector with another number will produce a second vector whose coordinates have all been multiplied by that single number.
__mul__
, __rmul__
, and __imul__
for multiplicationclass Vector:
...
def __mul__(self, other):
if isinstance(other, (int, float)):
coordinates = [coord * other for coord in self.coordinates]
return Vector(*coordinates)
return NotImplemented
if __name__ == "__main__":
v = Vector(1, 2)
print(v * 10)
❯ python point.py
Vector(10, 20)
Multiplication between vectors and numbers is commutative, so we implement __rmul__
in terms of __mul__
:
class Vector:
...
def __rmul__(self, other):
return self * other
if __name__ == "__main__":
v = Vector(1, 2)
print(v * 10)
print(0.1 * v)
❯ python point.py
Vector(10, 20)
Vector(0.1, 0.2)
Augmented multiplication is very similar to regular multiplication, although we return self
instead of a new object:
class Vector:
...
def __imul__(self, other):
if isinstance(other, (int, float)):
self.coordinates = tuple(coord * other for coord in self.coordinates)
return self
return NotImplemented
if __name__ == "__main__":
v = Vector(1, 2)
print(v, id(v))
v *= 10
print(v, id(v))
❯ python point.py
Vector(1, 2) 4301232784
Vector(10, 20) 4301232784
/
Given that addition, subtraction, and multiplication, are called __add__
, __sub__
, and __mul__
, respectively, one might assume that division is called __div__
.
However, /
is called __truediv__
.
That is to disambiguate from //
, which is then called __floordiv__
.
For division, we will say that a vector can be divided by a number or viceversa. In both cases, we will just take the number and map the division out across all coordinates of the vector.
__truediv__
, __rtruediv__
, and __itruediv__
for divisionclass Vector:
...
def __truediv__(self, other):
if isinstance(other, (int, float)):
coordinates = [coord / other for coord in self.coordinates]
return Vector(*coordinates)
return NotImplemented
def __rtruediv__(self, other):
if isinstance(other, (int, float)):
coordinates = [other / coord for coord in self.coordinates]
return Vector(*coordinates)
return NotImplemented
def __itruediv__(self, other):
if isinstance(other, (int, float)):
self.coordinates = tuple(coord / other for coord in self.coordinates)
return self
return NotImplemented
if __name__ == "__main__":
v = Vector(1, 2, 3, 4)
print(v / 2)
print(2 / v)
v /= 10
print(v)
The code above produces the following output:
❯ python point.py
Vector(0.5, 1.0, 1.5, 2.0)
Vector(2.0, 1.0, 0.6666666666666666, 0.5)
Vector(0.1, 0.2, 0.3, 0.4)
//
Floor division is //
and its dunder method is __floordiv__
, not to be confused with __truediv__
for the operation of division /
.
Much like with regular division, we will say that a vector can be divided by a number or viceversa. In both cases, we will just take the number and map the division out across all coordinates of the vector.
__floordiv__
, __rfloordiv__
, and __ifloordiv__
for divisionThe implementation below was essentially copied and pasted from the implementation of __truediv__
above, except I replaced the operation /
with //
...
class Vector:
...
def __floordiv__(self, other):
if isinstance(other, (int, float)):
coordinates = [coord // other for coord in self.coordinates]
return Vector(*coordinates)
return NotImplemented
def __rfloordiv__(self, other):
if isinstance(other, (int, float)):
coordinates = [other // coord for coord in self.coordinates]
return Vector(*coordinates)
return NotImplemented
def __ifloordiv__(self, other):
if isinstance(other, (int, float)):
self.coordinates = tuple(coord // other for coord in self.coordinates)
return self
return NotImplemented
if __name__ == "__main__":
v = Vector(9, 12, 23, 24)
print(v // 10)
print(30 // v)
v //= 10
print(v)
The code above produces the following output:
❯ python point.py
Vector(0, 1, 2, 2)
Vector(3, 2, 1, 1)
Vector(0, 1, 2, 2)
%
The binary operator %
is the operator for modulo.
To keep in line with other operators, using modulo between a number and a vector will apply the operation elementwise.
__mod__
, __rmod__
, and __imod__
for moduloclass Vector:
...
def __mod__(self, other):
if isinstance(other, (int, float)):
coordinates = [coord % other for coord in self.coordinates]
return Vector(*coordinates)
return NotImplemented
def __rmod__(self, other):
if isinstance(other, (int, float)):
coordinates = [other % coord for coord in self.coordinates]
return Vector(*coordinates)
return NotImplemented
def __imod__(self, other):
if isinstance(other, (int, float)):
self.coordinates = tuple(coord % other for coord in self.coordinates)
return self
return NotImplemented
if __name__ == "__main__":
v = Vector(9, 12, 23, 24)
print(v % 10)
print(30 % v)
v %= 10
print(v)
The code above produces the following output:
❯ python point.py
Vector(9, 2, 3, 4)
Vector(3, 6, 7, 6)
Vector(9, 2, 3, 4)
divmod
The builtin function divmod
puts together the operators /
(division) and %
(modulo).
The function call divmod(x, y)
should be equivalent to (x / y, x % y)
, so that is the behaviour we implement.
__divmod__
and __rdivmod__
for divmodNotice that there is no inplace/augmented operator __idivmod__
for us to implement because we cannot write the augmented operator divmod=
.
That does not make any sense in Python.
class Vector:
...
def __divmod__(self, other):
if isinstance(other, (int, float)):
return (self // other, self % other)
return NotImplemented
def __rdivmod__(self, other):
if isinstance(other, (int, float)):
return (other // self, other % self)
return NotImplemented
if __name__ == "__main__":
v = Vector(9, 12, 23, 24)
print(divmod(v, 10))
print(divmod(10, v))
The code above produces the following output:
❯ python point.py
(Vector(0, 1, 2, 2), Vector(9, 2, 3, 4))
(Vector(1, 0, 0, 0), Vector(1, 10, 10, 10))
**
and builtin function pow
The operation of exponentiation can be expressed both via the binary operator **
and the builtin function pow
.
The operator **
takes the left operand and raises it to the power of the right operand.
The builtin function pow
does a similar thing, except that pow
takes an optional third argument that is the modulo under which the exponentiation is computed.
For the implementation, we will allow either the left or right arguments of **
to be vectors, but the other one must be a number.
Furthermore, the only value that is acceptable as the optional third argument is a number.
__pow__
, __rpow__
, and __ipow__
for moduloclass Vector:
...
def __pow__(self, other, modulo=None):
if isinstance(other, (int, float)):
coordinates = [pow(coord, other, modulo) for coord in self.coordinates]
return Vector(*coordinates)
return NotImplemented
def __rpow__(self, other, modulo=None):
if isinstance(other, (int, float)):
coordinates = [pow(other, coord, modulo) for coord in self.coordinates]
return Vector(*coordinates)
return NotImplemented
def __ipow__(self, other, modulo=None):
if isinstance(other, (int, float)):
self.coordinates = tuple(
pow(coord, other, modulo) for coord in self.coordinates
)
return self
return NotImplemented
if __name__ == "__main__":
print(2 ** Vector(0, 1, 2, 3, 4))
# Some squares:
print(Vector(1, 9, 37, 45, 467) ** 2)
# Some squares, modulo 10
print(pow(Vector(1, 9, 37, 45, 467), 2, 10))
v = Vector(10, 100)
v **= 2
print(v)
The code above produces the following output:
❯ python point.py
Vector(1, 2, 4, 8, 16)
Vector(1, 81, 1369, 2025, 218089)
Vector(1, 1, 9, 5, 9)
Vector(100, 10000)
@
The binary operator @
is the operator for matrix multiplication.
At the time of writing, @
isn't used for any operations in vanilla Python but it is used in places like NumPy, where matrix multiplication is a common operation.
In our example, @
between two vectors will implement dot product, an operation that only works if the two vectors have the same length.
First, we multiply the corresponding coordinates of the two vectors together and then we sum those values.
Notice that @
between two vectors will produce a single number.
Thus, v1 @= v2
is an operation that may look like it does not make sense because v1
will cease to be a vector and it will become a number.
However, this behaviour is in line with vanilla Python:
>>> x = 3
>>> x *= [0]
>>> x
[0, 0, 0]
__matmul__
, __rmatmul__
, and __imatmul__
for moduloFor matrix multiplication, the only thing we support is matrix multiplication between two vectors.
Because of that, we do not need to implement __rmatmul__
.
So, we can either leave __rmatmul__
out, or we define it but the only statement we include is return NotImplemented
.
On a different note, because matrix multiplication between two vectors returns a number, there is also no point in defining __imatmul__
because the statement v1 @= v2
will not modify v1
in place.
Instead, it will replace v1
with the number result of the expression v1 @ v2
.
So, we could implement __imatmul__
to be equal to __matmul__
, but there is no point.
Thus, for matrix multiplication, we can boil our code down to:
class Vector:
...
def __matmul__(self, other):
if isinstance(other, Vector):
return sum(c1 * c2 for c1, c2 in zip(self.coordinates, other.coordinates))
return NotImplemented
def __rmatmul__(self, other):
return NotImplemented
if __name__ == "__main__":
v = Vector(3, 1, 2, 3)
print(v @ (~v))
v @= ~v
print(v)
The code above produces the following output:
❯ python point.py
0
0
<<
The binary operator <<
is the bitewise left shift operator.
(It is called bitewise because it operates on bits of integers.)
For vectors, we will implement the left shift operator with an integer argument and a vector argument, and it will rotate the coordinates of the vector the amount of times specified by the integer. We will do the same thing, regardless of whether the integer shows up on the left or on the right.
Here are some examples:
>>> v = Vector(1, 2, 3, 4)
>>> 0 << v
Vector(1, 2, 3, 4)
>>> v << 1 # Doesn't matter if `v` is on the left or right.
Vector(2, 3, 4, 1)
>>> 2 << v
Vector(3, 4, 1, 2)
__lshift__
, __rlshift__
, and __ilshift__
for bitwise left shiftclass Vector:
...
def __lshift__(self, other):
if isinstance(other, int):
coordinates = self.coordinates[other:] + self.coordinates[:other]
return Vector(*coordinates)
return NotImplemented
def __rlshift__(self, other):
if isinstance(other, int):
coordinates = self.coordinates[other:] + self.coordinates[:other]
return Vector(*coordinates)
return NotImplemented
def __ilshift__(self, other):
if isinstance(other, int):
self.coordinates = self.coordinates[other:] + self.coordinates[:other]
return self
return NotImplemented
if __name__ == "__main__":
v = Vector(1, 2, 3, 4)
print(0 << v)
print(v << 1)
print(2 << v)
v <<= 2
print(v)
The code above produces the following output:
❯ python point.py
Vector(1, 2, 3, 4)
Vector(2, 3, 4, 1)
Vector(3, 4, 1, 2)
Vector(3, 4, 1, 2)
>>
The binary operator >>
is the bitewise right shift operator.
Our implementation for the right shift operator will match the implementation for the left shift operator, seen above, but it will work in the other direction.
Here are some examples:
>>> v = Vector(1, 2, 3, 4)
>>> 0 >> v
Vector(1, 2, 3, 4)
>>> v >> 1 # Doesn't matter if `v` is on the left or right.
Vector(4, 1, 2, 3)
>>> 2 >> v
Vector(3, 4, 1, 2)
__rshift__
, __rrshift__
, and __irshift__
for bitwise right shiftThe implementation of the bitwise right shift is very similar to the implementation of the bitwise left shift and we use negative indices and slicing to get the shifting behaviour.
You can read this article about slicing to learn about the idiomatic slicing patterns being used below.
class Vector:
...
def __rshift__(self, other):
if isinstance(other, int):
coordinates = self.coordinates[other:] + self.coordinates[:other]
return Vector(*coordinates)
return NotImplemented
def __rrshift__(self, other):
if isinstance(other, int):
coordinates = self.coordinates[other:] + self.coordinates[:other]
return Vector(*coordinates)
return NotImplemented
def __irshift__(self, other):
if isinstance(other, int):
self.coordinates = self.coordinates[other:] + self.coordinates[:other]
return self
return NotImplemented
if __name__ == "__main__":
v = Vector(1, 2, 3, 4)
print(0 >> v)
print(v >> 1)
print(2 >> v)
v >>= 2
print(v)
The code above produces the following output:
❯ python point.py
Vector(1, 2, 3, 4)
Vector(4, 1, 2, 3)
Vector(3, 4, 1, 2)
Vector(3, 4, 1, 2)
&
The binary operator &
is the bitewise "and" operator, not to be confused with the keyword and
that operates on Boolean values.
We will use the bitwise and operator to implement concatenation of vectors, like so:
>>> Vector(1, 2) & Vector(3, 4)
Vector(1, 2, 3, 4)
__and__
, __rand__
, and __iand__
for bitwise andBecause we only defined the operator &
between instances of vectors, there is nothing we need to do inside __rand__
.
So, we provide an empty implementation that just returns NotImplemented
so that we can show we didn't forget __rand__
, but at the same time to say that it won't do anything for an expression x & v
, where x
is of a type other than Vector
.
class Vector:
...
def __and__(self, other):
if isinstance(other, Vector):
coordinates = self.coordinates + other.coordinates
return Vector(*coordinates)
return NotImplemented
def __rand__(self, other):
return NotImplemented
def __iand__(self, other):
if isinstance(other, Vector):
self.coordinates = self.coordinates + other.coordinates
return self
return NotImplemented
if __name__ == "__main__":
v = Vector(1, 2, 3, 4)
print(v & Vector(5, 6))
v &= Vector(5, 6)
print(v)
The code above produces the following output:
❯ python point.py
Vector(1, 2, 3, 4, 5, 6)
Vector(1, 2, 3, 4, 5, 6)
^
The binary operator ^
is the bitewise exclusive "or" operator.
We will use the bitwise exclusive or operator to implement an operation between numbers and vectors.
Given a number and a vector, we will create a vector of zeroes and ones:
(This operation has no particular meaning that I am aware of, it is just an example operation that we will implement here.)
Here are some examples:
>>> 1 ^ Vector(3, 0, 5)
Vector(0, 0, 1)
>>> 0 ^ Vector(3, 0, 5)
Vector(0, 1, 0)
>>> 73 ^ Vector(3, 0, 5)
Vector(1, 0, 0)
>>> Vector(3, 0, 5) ^ 73
Vector(1, 0, 0)
__xor__
, __rxor__
, and __ixor__
for bitwise exclusive or (xor)def sign(x):
if x < 0:
return 1
elif x == 0:
return 0
elif x > 0:
return 1
class Vector:
...
def __xor__(self, other):
if isinstance(other, (int, float)):
coordinates = [
int(sign(coord) == sign(other)) for coord in self.coordinates
]
return Vector(*coordinates)
return NotImplemented
def __rxor__(self, other):
if isinstance(other, (int, float)):
coordinates = [
int(sign(coord) == sign(other)) for coord in self.coordinates
]
return Vector(*coordinates)
return NotImplemented
def __ixor__(self, other):
if isinstance(other, (int, float)):
self.coordinates = tuple(
int(sign(coord) == sign(other)) for coord in self.coordinates
)
return self
return NotImplemented
if __name__ == "__main__":
print(1 ^ Vector(3, 0, 5))
print(0 ^ Vector(3, 0, 5))
print(73 ^ Vector(3, 0, 5))
print(Vector(3, 0, 5) ^ 73)
v = Vector(3, 0, 5)
v ^= 73
print(v)
The code above produces the following output:
❯ python point.py
Vector(0, 0, 1)
Vector(0, 1, 0)
Vector(1, 0, 0)
Vector(1, 0, 0)
Vector(1, 0, 0)

The binary operator 
is the bitewise "or" operator.
We will use the bitwise or operator to determine whether the left vector operand is a multiple of the right vector operand.
In other words, v1  v2
will check if there is a number x
such that v1 == x * v2
.
If there isn't, we will return None
.
(This operation also has no particular meaning that I am aware of, it is just an example operation that we will implement here.)
Here are some examples:
>>> Vector(6)  Vector(2)
3
>>> Vector(2, 4)  Vector(1, 2)
2
>>> Vector(2, 4)  Vector(8, 16)
0.25
>>> Vector(2, 4)  Vector(1, 4)
None
__or__
, __ror__
, and __ior__
for bitwise orThe bitwise or only operates between vectors, so there is no behaviour that we can implement inside __ror__
.
For that reason, we just return NotImplemented
.
Leaving out __ror__
would have the same effect.
Because the operator 
produces numbers when applied to two vectors, it also doesn't make sense to implement __ior__
, although we could implement __ior__
to be exactly the same as __or__
.
class Vector:
...
def __or__(self, other):
if isinstance(other, Vector):
mult = (
self.coordinates[0] / other.coordinates[0]
if other.coordinates[0]
else 0
)
for c1, c2 in zip(self.coordinates, other.coordinates):
if c1 != mult * c2:
return None
return mult
return NotImplemented
def __ror__(self, other):
return NotImplemented
if __name__ == "__main__":
print(Vector(6)  Vector(2))
print(Vector(2, 4)  Vector(1, 2))
print(Vector(2, 4)  Vector(8, 16))
print(Vector(2, 4)  Vector(1, 4))
print(Vector(0, 0)  Vector(0, 0))
print(Vector(4, 2)  Vector(0, 1))
The code above produces the following output:
❯ python point.py
3.0
2.0
0.25
None
0
None
Vector
If you want to see the full implementation of the class Vector
, go ahead and take a look below.
+
and 
so that a ValueError
is raised when the two vectors being added/subtracted do not have the same length.*
so that we can also multiply vectors together.
In order to be able to multiply two vectors together, the two vectors need to have the same length and then you'll multiply corresponding coordinates together./
and //
so that we can also divide vectors together.
In order to be able to divide two vectors together, the two vectors need to have the same length and then you'll divide corresponding coordinates.__ror__
and __rmatmul__
.__imatmul__
and __ior__
and see if the fact that those two methods return numbers instead of vectors breaks expressions like v1 = v2
and v1 @= v2
.Here's the main takeaway of this Pydon't, for you, on a silver platter:
“The behaviour of arithmetic operators in Python is implemented via their respective dunder methods (and the reversed and inplace variants) and the singleton value
NotImplemented
.”
This Pydon't showed you that:
NotImplemented
is used behind the scenes to flag operator/argument(s) combinations that cannot be handled;NotImplemented
so that Python knows what methods to call;NotImplemented
is distinct from the exception NotImplementedError
;r
prepended to the name;NotImplemented
); ori
prepended to the name;+=
and =
; andAdditionally, we also provided a custom class that implements virtually every single arithmetic dunder method (reversed and inplace variants included) and we provided a couple of exercises for you to practise.
If you liked this Pydon't be sure to leave a reaction below and share this with your friends and fellow Pythonistas. Also, [don't forget to subscribe to the newsletter] so you don't miss a single Pydon't!
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